Optimal. Leaf size=491 \[ -\frac {a^2 b \left (a^2+2 b^2\right ) \log \left (a+b \tanh ^3(c+d x)\right )}{d \left (a^2-b^2\right )^3}-\frac {a^{2/3} \sqrt [3]{b} \left (3 a^{4/3} b^{2/3}+a^2-b^2\right ) \tan ^{-1}\left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} \tanh (c+d x)}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt {3} d \left (a^{2/3} b^{2/3}+a^{4/3}+b^{4/3}\right )^3}+\frac {a^{2/3} \sqrt [3]{b} \left (a^4+7 a^2 b^2+3 a^{2/3} b^{4/3} \left (2 a^2+b^2\right )+b^4\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} \tanh (c+d x)+b^{2/3} \tanh ^2(c+d x)\right )}{6 d \left (a^2-b^2\right )^3}-\frac {a^{2/3} \sqrt [3]{b} \left (a^4+7 a^2 b^2+3 a^{2/3} b^{4/3} \left (2 a^2+b^2\right )+b^4\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} \tanh (c+d x)\right )}{3 d \left (a^2-b^2\right )^3}-\frac {5 a-b}{16 d (a+b)^2 (1-\tanh (c+d x))}+\frac {5 a+b}{16 d (a-b)^2 (\tanh (c+d x)+1)}+\frac {1}{16 d (a+b) (1-\tanh (c+d x))^2}-\frac {1}{16 d (a-b) (\tanh (c+d x)+1)^2}-\frac {3 a (a-5 b) \log (1-\tanh (c+d x))}{16 d (a+b)^3}+\frac {3 a (a+5 b) \log (\tanh (c+d x)+1)}{16 d (a-b)^3} \]
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Rubi [A] time = 0.89, antiderivative size = 491, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 10, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.435, Rules used = {3663, 6725, 1871, 1860, 31, 634, 617, 204, 628, 260} \[ -\frac {a^2 b \left (a^2+2 b^2\right ) \log \left (a+b \tanh ^3(c+d x)\right )}{d \left (a^2-b^2\right )^3}+\frac {a^{2/3} \sqrt [3]{b} \left (7 a^2 b^2+3 a^{2/3} b^{4/3} \left (2 a^2+b^2\right )+a^4+b^4\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} \tanh (c+d x)+b^{2/3} \tanh ^2(c+d x)\right )}{6 d \left (a^2-b^2\right )^3}-\frac {a^{2/3} \sqrt [3]{b} \left (7 a^2 b^2+3 a^{2/3} b^{4/3} \left (2 a^2+b^2\right )+a^4+b^4\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} \tanh (c+d x)\right )}{3 d \left (a^2-b^2\right )^3}-\frac {a^{2/3} \sqrt [3]{b} \left (3 a^{4/3} b^{2/3}+a^2-b^2\right ) \tan ^{-1}\left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} \tanh (c+d x)}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt {3} d \left (a^{2/3} b^{2/3}+a^{4/3}+b^{4/3}\right )^3}-\frac {5 a-b}{16 d (a+b)^2 (1-\tanh (c+d x))}+\frac {5 a+b}{16 d (a-b)^2 (\tanh (c+d x)+1)}+\frac {1}{16 d (a+b) (1-\tanh (c+d x))^2}-\frac {1}{16 d (a-b) (\tanh (c+d x)+1)^2}-\frac {3 a (a-5 b) \log (1-\tanh (c+d x))}{16 d (a+b)^3}+\frac {3 a (a+5 b) \log (\tanh (c+d x)+1)}{16 d (a-b)^3} \]
Antiderivative was successfully verified.
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Rule 31
Rule 204
Rule 260
Rule 617
Rule 628
Rule 634
Rule 1860
Rule 1871
Rule 3663
Rule 6725
Rubi steps
\begin {align*} \int \frac {\sinh ^4(c+d x)}{a+b \tanh ^3(c+d x)} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {x^4}{\left (1-x^2\right )^3 \left (a+b x^3\right )} \, dx,x,\tanh (c+d x)\right )}{d}\\ &=\frac {\operatorname {Subst}\left (\int \left (-\frac {1}{8 (a+b) (-1+x)^3}+\frac {-5 a+b}{16 (a+b)^2 (-1+x)^2}-\frac {3 a (a-5 b)}{16 (a+b)^3 (-1+x)}+\frac {1}{8 (a-b) (1+x)^3}+\frac {-5 a-b}{16 (a-b)^2 (1+x)^2}+\frac {3 a (a+5 b)}{16 (a-b)^3 (1+x)}+\frac {a b \left (-3 a b \left (2 a^2+b^2\right )+\left (a^4+7 a^2 b^2+b^4\right ) x-3 a b \left (a^2+2 b^2\right ) x^2\right )}{\left (a^2-b^2\right )^3 \left (a+b x^3\right )}\right ) \, dx,x,\tanh (c+d x)\right )}{d}\\ &=-\frac {3 a (a-5 b) \log (1-\tanh (c+d x))}{16 (a+b)^3 d}+\frac {3 a (a+5 b) \log (1+\tanh (c+d x))}{16 (a-b)^3 d}+\frac {1}{16 (a+b) d (1-\tanh (c+d x))^2}-\frac {5 a-b}{16 (a+b)^2 d (1-\tanh (c+d x))}-\frac {1}{16 (a-b) d (1+\tanh (c+d x))^2}+\frac {5 a+b}{16 (a-b)^2 d (1+\tanh (c+d x))}+\frac {(a b) \operatorname {Subst}\left (\int \frac {-3 a b \left (2 a^2+b^2\right )+\left (a^4+7 a^2 b^2+b^4\right ) x-3 a b \left (a^2+2 b^2\right ) x^2}{a+b x^3} \, dx,x,\tanh (c+d x)\right )}{\left (a^2-b^2\right )^3 d}\\ &=-\frac {3 a (a-5 b) \log (1-\tanh (c+d x))}{16 (a+b)^3 d}+\frac {3 a (a+5 b) \log (1+\tanh (c+d x))}{16 (a-b)^3 d}+\frac {1}{16 (a+b) d (1-\tanh (c+d x))^2}-\frac {5 a-b}{16 (a+b)^2 d (1-\tanh (c+d x))}-\frac {1}{16 (a-b) d (1+\tanh (c+d x))^2}+\frac {5 a+b}{16 (a-b)^2 d (1+\tanh (c+d x))}+\frac {(a b) \operatorname {Subst}\left (\int \frac {-3 a b \left (2 a^2+b^2\right )+\left (a^4+7 a^2 b^2+b^4\right ) x}{a+b x^3} \, dx,x,\tanh (c+d x)\right )}{\left (a^2-b^2\right )^3 d}-\frac {\left (3 a^2 b^2 \left (a^2+2 b^2\right )\right ) \operatorname {Subst}\left (\int \frac {x^2}{a+b x^3} \, dx,x,\tanh (c+d x)\right )}{\left (a^2-b^2\right )^3 d}\\ &=-\frac {3 a (a-5 b) \log (1-\tanh (c+d x))}{16 (a+b)^3 d}+\frac {3 a (a+5 b) \log (1+\tanh (c+d x))}{16 (a-b)^3 d}-\frac {a^2 b \left (a^2+2 b^2\right ) \log \left (a+b \tanh ^3(c+d x)\right )}{\left (a^2-b^2\right )^3 d}+\frac {1}{16 (a+b) d (1-\tanh (c+d x))^2}-\frac {5 a-b}{16 (a+b)^2 d (1-\tanh (c+d x))}-\frac {1}{16 (a-b) d (1+\tanh (c+d x))^2}+\frac {5 a+b}{16 (a-b)^2 d (1+\tanh (c+d x))}+\frac {\left (\sqrt [3]{a} b^{2/3}\right ) \operatorname {Subst}\left (\int \frac {\sqrt [3]{a} \left (-6 a b^{4/3} \left (2 a^2+b^2\right )+\sqrt [3]{a} \left (a^4+7 a^2 b^2+b^4\right )\right )+\sqrt [3]{b} \left (3 a b^{4/3} \left (2 a^2+b^2\right )+\sqrt [3]{a} \left (a^4+7 a^2 b^2+b^4\right )\right ) x}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx,x,\tanh (c+d x)\right )}{3 \left (a^2-b^2\right )^3 d}-\frac {\left (a^{2/3} b^{2/3} \left (a^4+7 a^2 b^2+b^4+3 a^{2/3} b^{4/3} \left (2 a^2+b^2\right )\right )\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{a}+\sqrt [3]{b} x} \, dx,x,\tanh (c+d x)\right )}{3 \left (a^2-b^2\right )^3 d}\\ &=-\frac {3 a (a-5 b) \log (1-\tanh (c+d x))}{16 (a+b)^3 d}+\frac {3 a (a+5 b) \log (1+\tanh (c+d x))}{16 (a-b)^3 d}-\frac {a^{2/3} \sqrt [3]{b} \left (a^4+7 a^2 b^2+b^4+3 a^{2/3} b^{4/3} \left (2 a^2+b^2\right )\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} \tanh (c+d x)\right )}{3 \left (a^2-b^2\right )^3 d}-\frac {a^2 b \left (a^2+2 b^2\right ) \log \left (a+b \tanh ^3(c+d x)\right )}{\left (a^2-b^2\right )^3 d}+\frac {1}{16 (a+b) d (1-\tanh (c+d x))^2}-\frac {5 a-b}{16 (a+b)^2 d (1-\tanh (c+d x))}-\frac {1}{16 (a-b) d (1+\tanh (c+d x))^2}+\frac {5 a+b}{16 (a-b)^2 d (1+\tanh (c+d x))}+\frac {\left (a b^{2/3} \left (a^2+3 a^{4/3} b^{2/3}-b^2\right )\right ) \operatorname {Subst}\left (\int \frac {1}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx,x,\tanh (c+d x)\right )}{2 \left (a^{4/3}+a^{2/3} b^{2/3}+b^{4/3}\right )^3 d}+\frac {\left (a^{2/3} \sqrt [3]{b} \left (a^4+7 a^2 b^2+b^4+3 a^{2/3} b^{4/3} \left (2 a^2+b^2\right )\right )\right ) \operatorname {Subst}\left (\int \frac {-\sqrt [3]{a} \sqrt [3]{b}+2 b^{2/3} x}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx,x,\tanh (c+d x)\right )}{6 \left (a^2-b^2\right )^3 d}\\ &=-\frac {3 a (a-5 b) \log (1-\tanh (c+d x))}{16 (a+b)^3 d}+\frac {3 a (a+5 b) \log (1+\tanh (c+d x))}{16 (a-b)^3 d}-\frac {a^{2/3} \sqrt [3]{b} \left (a^4+7 a^2 b^2+b^4+3 a^{2/3} b^{4/3} \left (2 a^2+b^2\right )\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} \tanh (c+d x)\right )}{3 \left (a^2-b^2\right )^3 d}+\frac {a^{2/3} \sqrt [3]{b} \left (a^4+7 a^2 b^2+b^4+3 a^{2/3} b^{4/3} \left (2 a^2+b^2\right )\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} \tanh (c+d x)+b^{2/3} \tanh ^2(c+d x)\right )}{6 \left (a^2-b^2\right )^3 d}-\frac {a^2 b \left (a^2+2 b^2\right ) \log \left (a+b \tanh ^3(c+d x)\right )}{\left (a^2-b^2\right )^3 d}+\frac {1}{16 (a+b) d (1-\tanh (c+d x))^2}-\frac {5 a-b}{16 (a+b)^2 d (1-\tanh (c+d x))}-\frac {1}{16 (a-b) d (1+\tanh (c+d x))^2}+\frac {5 a+b}{16 (a-b)^2 d (1+\tanh (c+d x))}+\frac {\left (a^{2/3} \sqrt [3]{b} \left (a^2+3 a^{4/3} b^{2/3}-b^2\right )\right ) \operatorname {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1-\frac {2 \sqrt [3]{b} \tanh (c+d x)}{\sqrt [3]{a}}\right )}{\left (a^{4/3}+a^{2/3} b^{2/3}+b^{4/3}\right )^3 d}\\ &=-\frac {a^{2/3} \sqrt [3]{b} \left (a^2+3 a^{4/3} b^{2/3}-b^2\right ) \tan ^{-1}\left (\frac {1-\frac {2 \sqrt [3]{b} \tanh (c+d x)}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{\sqrt {3} \left (a^{4/3}+a^{2/3} b^{2/3}+b^{4/3}\right )^3 d}-\frac {3 a (a-5 b) \log (1-\tanh (c+d x))}{16 (a+b)^3 d}+\frac {3 a (a+5 b) \log (1+\tanh (c+d x))}{16 (a-b)^3 d}-\frac {a^{2/3} \sqrt [3]{b} \left (a^4+7 a^2 b^2+b^4+3 a^{2/3} b^{4/3} \left (2 a^2+b^2\right )\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} \tanh (c+d x)\right )}{3 \left (a^2-b^2\right )^3 d}+\frac {a^{2/3} \sqrt [3]{b} \left (a^4+7 a^2 b^2+b^4+3 a^{2/3} b^{4/3} \left (2 a^2+b^2\right )\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} \tanh (c+d x)+b^{2/3} \tanh ^2(c+d x)\right )}{6 \left (a^2-b^2\right )^3 d}-\frac {a^2 b \left (a^2+2 b^2\right ) \log \left (a+b \tanh ^3(c+d x)\right )}{\left (a^2-b^2\right )^3 d}+\frac {1}{16 (a+b) d (1-\tanh (c+d x))^2}-\frac {5 a-b}{16 (a+b)^2 d (1-\tanh (c+d x))}-\frac {1}{16 (a-b) d (1+\tanh (c+d x))^2}+\frac {5 a+b}{16 (a-b)^2 d (1+\tanh (c+d x))}\\ \end {align*}
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Mathematica [C] time = 4.83, size = 645, normalized size = 1.31 \[ \frac {3 \left (a (a-b) \left (12 \left (a^2-6 a b+5 b^2\right ) (c+d x)+(a+b)^2 \sinh (4 (c+d x))\right )-8 a \left (a^3+a^2 b+2 a b^2+2 b^3\right ) \sinh (2 (c+d x))+4 b \left (5 a^3+5 a^2 b+a b^2+b^3\right ) \cosh (2 (c+d x))-\left (b (a-b) (a+b)^2 \cosh (4 (c+d x))\right )\right )-32 a b \text {RootSum}\left [\text {$\#$1}^3 a+\text {$\#$1}^3 b+3 \text {$\#$1}^2 a-3 \text {$\#$1}^2 b+3 \text {$\#$1} a+3 \text {$\#$1} b+a-b\& ,\frac {5 \text {$\#$1}^2 a^3 \log \left (e^{2 (c+d x)}-\text {$\#$1}\right )-10 \text {$\#$1}^2 a^3 c-10 \text {$\#$1}^2 a^3 d x-10 \text {$\#$1}^2 a^2 b \log \left (e^{2 (c+d x)}-\text {$\#$1}\right )+20 \text {$\#$1}^2 a^2 b c+20 \text {$\#$1}^2 a^2 b d x+10 \text {$\#$1}^2 a b^2 \log \left (e^{2 (c+d x)}-\text {$\#$1}\right )-20 \text {$\#$1}^2 a b^2 c-20 \text {$\#$1}^2 a b^2 d x-2 \text {$\#$1}^2 b^3 \log \left (e^{2 (c+d x)}-\text {$\#$1}\right )+4 \text {$\#$1}^2 b^3 c+4 \text {$\#$1}^2 b^3 d x+3 a^3 \log \left (e^{2 (c+d x)}-\text {$\#$1}\right )+4 \text {$\#$1} a^3 \log \left (e^{2 (c+d x)}-\text {$\#$1}\right )-8 \text {$\#$1} a^3 c-8 \text {$\#$1} a^3 d x-2 \text {$\#$1} a^2 b \log \left (e^{2 (c+d x)}-\text {$\#$1}\right )+4 \text {$\#$1} a^2 b c+4 \text {$\#$1} a^2 b d x+6 a b^2 \log \left (e^{2 (c+d x)}-\text {$\#$1}\right )-4 \text {$\#$1} a b^2 \log \left (e^{2 (c+d x)}-\text {$\#$1}\right )+8 \text {$\#$1} a b^2 c+8 \text {$\#$1} a b^2 d x+2 \text {$\#$1} b^3 \log \left (e^{2 (c+d x)}-\text {$\#$1}\right )-4 \text {$\#$1} b^3 c-4 \text {$\#$1} b^3 d x-6 a^3 c-6 a^3 d x-12 a b^2 c-12 a b^2 d x}{\text {$\#$1}^2 a-\text {$\#$1}^2 b+2 \text {$\#$1} a+2 \text {$\#$1} b+a-b}\& \right ]}{96 d (a-b)^2 (a+b)^3} \]
Antiderivative was successfully verified.
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fricas [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.76, size = 362, normalized size = 0.74 \[ \frac {\frac {24 \, {\left (a^{2} + 5 \, a b\right )} d x}{a^{3} - 3 \, a^{2} b + 3 \, a b^{2} - b^{3}} - \frac {{\left (18 \, a^{2} e^{\left (4 \, d x + 4 \, c\right )} + 90 \, a b e^{\left (4 \, d x + 4 \, c\right )} - 8 \, a^{2} e^{\left (2 \, d x + 2 \, c\right )} + 4 \, a b e^{\left (2 \, d x + 2 \, c\right )} + 4 \, b^{2} e^{\left (2 \, d x + 2 \, c\right )} + a^{2} - 2 \, a b + b^{2}\right )} e^{\left (-4 \, d x\right )}}{a^{3} e^{\left (4 \, c\right )} - 3 \, a^{2} b e^{\left (4 \, c\right )} + 3 \, a b^{2} e^{\left (4 \, c\right )} - b^{3} e^{\left (4 \, c\right )}} - \frac {64 \, {\left (a^{4} b + 2 \, a^{2} b^{3}\right )} \log \left ({\left | a e^{\left (6 \, d x + 6 \, c\right )} + b e^{\left (6 \, d x + 6 \, c\right )} + 3 \, a e^{\left (4 \, d x + 4 \, c\right )} - 3 \, b e^{\left (4 \, d x + 4 \, c\right )} + 3 \, a e^{\left (2 \, d x + 2 \, c\right )} + 3 \, b e^{\left (2 \, d x + 2 \, c\right )} + a - b \right |}\right )}{a^{6} - 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} - b^{6}} + \frac {a e^{\left (4 \, d x + 24 \, c\right )} + b e^{\left (4 \, d x + 24 \, c\right )} - 8 \, a e^{\left (2 \, d x + 22 \, c\right )} + 4 \, b e^{\left (2 \, d x + 22 \, c\right )}}{a^{2} e^{\left (20 \, c\right )} + 2 \, a b e^{\left (20 \, c\right )} + b^{2} e^{\left (20 \, c\right )}}}{64 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.51, size = 603, normalized size = 1.23 \[ -\frac {a b \left (\munderset {\textit {\_R} =\RootOf \left (a \,\textit {\_Z}^{6}+3 a \,\textit {\_Z}^{4}+8 b \,\textit {\_Z}^{3}+3 a \,\textit {\_Z}^{2}+a \right )}{\sum }\frac {\left (3 a^{2} \left (a^{2}+2 b^{2}\right ) \textit {\_R}^{5}+3 a b \left (-2 a^{2}-b^{2}\right ) \textit {\_R}^{4}+2 \left (4 a^{4}+13 a^{2} b^{2}+b^{4}\right ) \textit {\_R}^{3}+12 a b \left (a^{2}+2 b^{2}\right ) \textit {\_R}^{2}+\left (a^{4}-8 a^{2} b^{2}-2 b^{4}\right ) \textit {\_R} +6 a^{3} b +3 a \,b^{3}\right ) \ln \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )-\textit {\_R} \right )}{\textit {\_R}^{5} a +2 \textit {\_R}^{3} a +4 \textit {\_R}^{2} b +\textit {\_R} a}\right )}{3 d \left (a -b \right )^{3} \left (a +b \right )^{3}}+\frac {8}{d \left (32 a +32 b \right ) \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{4}}+\frac {32}{d \left (64 a +64 b \right ) \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{3}}-\frac {a}{8 d \left (a +b \right )^{2} \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{2}}+\frac {5 b}{8 d \left (a +b \right )^{2} \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{2}}-\frac {3 a}{8 d \left (a +b \right )^{2} \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}+\frac {3 b}{8 d \left (a +b \right )^{2} \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}-\frac {3 a^{2} \ln \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{8 d \left (a +b \right )^{3}}+\frac {15 a \ln \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) b}{8 d \left (a +b \right )^{3}}-\frac {8}{d \left (32 a -32 b \right ) \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{4}}+\frac {32}{d \left (64 a -64 b \right ) \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}+\frac {a}{8 d \left (a -b \right )^{2} \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}+\frac {5 b}{8 d \left (a -b \right )^{2} \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}-\frac {3 a}{8 d \left (a -b \right )^{2} \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}-\frac {3 b}{8 d \left (a -b \right )^{2} \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}+\frac {3 a^{2} \ln \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{8 d \left (a -b \right )^{3}}+\frac {15 a \ln \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right ) b}{8 d \left (a -b \right )^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -6 \, a^{4} b {\left (\frac {-{\left (a - b\right )} \int \frac {1}{{\left (a e^{\left (6 \, c\right )} + b e^{\left (6 \, c\right )}\right )} e^{\left (6 \, d x\right )} + 3 \, {\left (a e^{\left (4 \, c\right )} - b e^{\left (4 \, c\right )}\right )} e^{\left (4 \, d x\right )} + 3 \, {\left (a e^{\left (2 \, c\right )} + b e^{\left (2 \, c\right )}\right )} e^{\left (2 \, d x\right )} + a - b}\,{d x} + x}{a^{6} - 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} - b^{6}} - \frac {d x + c}{{\left (a^{6} - 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} - b^{6}\right )} d}\right )} - 12 \, a^{2} b^{3} {\left (\frac {-{\left (a - b\right )} \int \frac {1}{{\left (a e^{\left (6 \, c\right )} + b e^{\left (6 \, c\right )}\right )} e^{\left (6 \, d x\right )} + 3 \, {\left (a e^{\left (4 \, c\right )} - b e^{\left (4 \, c\right )}\right )} e^{\left (4 \, d x\right )} + 3 \, {\left (a e^{\left (2 \, c\right )} + b e^{\left (2 \, c\right )}\right )} e^{\left (2 \, d x\right )} + a - b}\,{d x} + x}{a^{6} - 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} - b^{6}} - \frac {d x + c}{{\left (a^{6} - 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} - b^{6}\right )} d}\right )} + \frac {0 \, }{a^{5} + a^{4} b - 2 \, a^{3} b^{2} - 2 \, a^{2} b^{3} + a b^{4} + b^{5}} - \frac {0 \, }{a^{5} + a^{4} b - 2 \, a^{3} b^{2} - 2 \, a^{2} b^{3} + a b^{4} + b^{5}} + \frac {0 \, }{a^{5} + a^{4} b - 2 \, a^{3} b^{2} - 2 \, a^{2} b^{3} + a b^{4} + b^{5}} - \frac {0 \, }{a^{5} + a^{4} b - 2 \, a^{3} b^{2} - 2 \, a^{2} b^{3} + a b^{4} + b^{5}} + \frac {0 \, }{a^{5} + a^{4} b - 2 \, a^{3} b^{2} - 2 \, a^{2} b^{3} + a b^{4} + b^{5}} - \frac {0 \, }{a^{5} + a^{4} b - 2 \, a^{3} b^{2} - 2 \, a^{2} b^{3} + a b^{4} + b^{5}} - \frac {0 \, }{a^{5} + a^{4} b - 2 \, a^{3} b^{2} - 2 \, a^{2} b^{3} + a b^{4} + b^{5}} + \frac {0 \, }{a^{5} + a^{4} b - 2 \, a^{3} b^{2} - 2 \, a^{2} b^{3} + a b^{4} + b^{5}} - \frac {{\left (a^{4} + 2 \, a^{3} b - 2 \, a b^{3} - b^{4} - 24 \, {\left (a^{4} d e^{\left (4 \, c\right )} - 7 \, a^{3} b d e^{\left (4 \, c\right )} + 11 \, a^{2} b^{2} d e^{\left (4 \, c\right )} - 5 \, a b^{3} d e^{\left (4 \, c\right )}\right )} x e^{\left (4 \, d x\right )} - {\left (a^{4} e^{\left (8 \, c\right )} - 2 \, a^{2} b^{2} e^{\left (8 \, c\right )} + b^{4} e^{\left (8 \, c\right )}\right )} e^{\left (8 \, d x\right )} + 4 \, {\left (2 \, a^{4} e^{\left (6 \, c\right )} - 3 \, a^{3} b e^{\left (6 \, c\right )} - a^{2} b^{2} e^{\left (6 \, c\right )} + 3 \, a b^{3} e^{\left (6 \, c\right )} - b^{4} e^{\left (6 \, c\right )}\right )} e^{\left (6 \, d x\right )} - 4 \, {\left (2 \, a^{4} e^{\left (2 \, c\right )} + 7 \, a^{3} b e^{\left (2 \, c\right )} + 9 \, a^{2} b^{2} e^{\left (2 \, c\right )} + 5 \, a b^{3} e^{\left (2 \, c\right )} + b^{4} e^{\left (2 \, c\right )}\right )} e^{\left (2 \, d x\right )}\right )} e^{\left (-4 \, d x\right )}}{64 \, {\left (a^{5} d e^{\left (4 \, c\right )} + a^{4} b d e^{\left (4 \, c\right )} - 2 \, a^{3} b^{2} d e^{\left (4 \, c\right )} - 2 \, a^{2} b^{3} d e^{\left (4 \, c\right )} + a b^{4} d e^{\left (4 \, c\right )} + b^{5} d e^{\left (4 \, c\right )}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.36, size = 3313, normalized size = 6.75 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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